[SOLVED] Extracting used memory as a percentage from free -m

[chimak111]

This is just some code to get used memory as a percentage:

free -m | awk ' $1 == "Mem:" { print "(("$3 "/" $2 ")" "*100)"}' | bc -l | cut -d '.' -f -1

Can it be simplified?

[andystmartin]

Here's a version that does all the dirty work in awk:

free -m | awk '$1 == "Mem:" { printf "%.0f\n", (($3 / $2 ) *100)}'

[chimak111]

Here's a version that does all the dirty work in awk:

free -m | awk '$1 == "Mem:" { printf "%.0f\n", (($3 / $2 ) *100)}'

Great! Thank you!