OK, how about this:
The formula for finding the sum of an infinite geometric sequence is S = a1 / (1 - r), where S is the sum, a1 is the first term in the sequence, and r is the common ratio.
In the case of 0.999... we get S = 0.9 / (1 - 1/10) = 0.9 / 0.9 = 1
Source: http://www.bungie.net/it-it/Forum/Post?id=61117593
Also (from the same source) let's say that x = 0.999...
10x = 9.999...
10x - x = 9x = 9.000...
If 9x = 9.000... then x must equal 1.000..., even though we stipulated at the beginning that x = 0.999... therefore 0.999... and 1.000... must be the same.
From what I've been reading, amongst top mathematicians the notion that 0.999... equals 1 isn't even controversial; it's broadly accepted. I know that's the logical fallacy of 'argument from authority', but it'll do for me.
The formula for finding the sum of an infinite geometric sequence is S = a1 / (1 - r), where S is the sum, a1 is the first term in the sequence, and r is the common ratio.
In the case of 0.999... we get S = 0.9 / (1 - 1/10) = 0.9 / 0.9 = 1
Source: http://www.bungie.net/it-it/Forum/Post?id=61117593
Also (from the same source) let's say that x = 0.999...
10x = 9.999...
10x - x = 9x = 9.000...
If 9x = 9.000... then x must equal 1.000..., even though we stipulated at the beginning that x = 0.999... therefore 0.999... and 1.000... must be the same.
From what I've been reading, amongst top mathematicians the notion that 0.999... equals 1 isn't even controversial; it's broadly accepted. I know that's the logical fallacy of 'argument from authority', but it'll do for me.
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